16x^2+56x+24=0

Solution for 16x^2+56x+24=0 equation:

16x^2+56x+24=0

a = 16; b = 56; c = +24;
Δ = b2-4ac
Δ = 562-4·16·24
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(56)-40}{2*16}=\frac{-96}{32}
=-3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(56)+40}{2*16}=\frac{-16}{32}
=-1/2
$